Do you know the answer?

B.

This is a multiple choice test. Once you eliminate three answers, you pick the fourth answer and move on to the next question. It can't be A, C, or D, for reasons that I understand. There's a non-zero chance that it's B for a reason that I don't understand.

If there is no correct answer, then there's no point hemming and hawing about it.

B. Final answer.

This is a self-referential paradox — a classic logic puzzle designed to be tricky. Let’s break it down:

Step-by-step analysis:

1. How many choices? There are 4 possible answers, so if we pick one randomly, the chance of picking any specific one is 1 in 4 = 25%.
2. How many answers say “25%”? Two.
3. That means the probability of randomly choosing an answer that says “25%” is 2 in 4 = 50%.
4. But if the correct answer is 50%, then only one option says “50%” — which is (c). So the probability of picking it at random is 1 in 4 = 25%, contradicting the idea that 50% is correct.
5. If the correct answer is 25%, then two options say that — a and d. So the chance of picking one of those at random is 50%, not 25% — again a contradiction.
6. Similarly, if 60% is correct (only one option), then the chance of picking it randomly is 25%, which again makes it incorrect.

Conclusion: Any choice leads to a contradiction. This is a self-referential paradox, meaning the question breaks logical consistency. There is no consistent correct answer.

The question is malformed and the correct answer isn't listed in the multiple choices. Therefore the correct answer is 0%

It's 0%, because 0% isn't on the list and therefore you have no chance of picking it. It's the only answer consistent with itself. All other chances cause a kind of paradox-loop.

This is a paradox, and I don't think there is a correct answer, at least not as a letter choice. The correct answer is to explain the paradox.

It's probably graded by a computer, and a) or d) is a fake answer, since the automated system doesn't support multiple right answers.

I'm going to go with 25% chance if picking random, and a 50% chance if picking between a) and d).
If it's graded by a human, the correct answer is f) + u)

This can also be used a great example of proof by contradiction: There is no correct answer in the options. Proof: Assume there was a correct answer in the options. Then it must be either 25%, 50% or 60%. Now we make a case distinction.

(A) Assume it was 25. Then there would be two of four correct options yielding in a probability of 50%. Therefore 50 must be the correct answer. -> contradiction.

(B) Assume it was 50. Then there would be one of four correct options yielding in a probability of 25%. Therefore the answer is 25. -> contradiction.

(C) Assume it was 60%. Since only 0,1,2,3 or 4 of the answers can be correct the probability of choosing the right answer must be one of 0% 25% 50% 75% or 100%. -> contradiction.

Because of (A), (B) and (C), it cannot be 25, 50% or 60%. -> contradiction.

42

C, which means A or D, which means C, which means...

This seems like a version of the Liar paradox. Assume "this statement is false" is true. Is the statement true or false?

There are a bunch of ways to break the paradox, but they all require using a system that doesn't allow it to exist. For example, a system where truth is a percentage so a statement being 50% true is allowed.

For this question, one way to break the paradox would be to say that multiple choice answers must all be unique and repeated answers are ignored. Using that rule, this question only has the answers a) 25%, b) 60%, and c) 50%, and none of them are correct. There's a 0% chance of getting the correct answer.

You can never answer this question correctly. If the correct answer is 25% there's a 50% chance you guess correctly but that would make the 25% wrong.

But if the answer is the 50% then it implies that 25% is correct which implies that 50% is wrong.

We reach a contradiction for both 25% and 50% making the correct answer to make the whole statement truthy 0%.

50/50, you either guess it right or you dont

Paradoxes aside, if you're given multiple choices without the guarantee that any of them are correct, you can't assign a chance of picking the right one at random anyway.

Thanks for making me laugh all alone in my car before heading in to work. I wish I could give you an award. Cheers!

What's the correct value if the answer is not picked at random but the test takers can choose freely?

The answer is not available. The answer is 0 Percent. Each answer, if chosen, would be incorrect. If 0% was an answer, it would be the correct one despite being a 25% chance. Of course, if one 25% was there, that would be the correct answer.

This only produces a paradox if you fall for the usual fallacy that "at random" necessarily means "with uniform probability".

For example, I would pick an answer at random by rolling a fair cubic die and picking a) if it rolls a 1, b) on a 2, d) on a 3 or c) otherwise so for me the answer is c) 50%.

However, as it specifies that you are to pick at random the existence, uniqueness and value of the correct answer depends on the specific distribution you choose.

If you're choosing the answer, then there is 100% chance of being correct. Since none of these answers is 100%, the chance is 0%.

0%

The only winning move is not to choose

I see 25% twice so my bet is on 50%.

It was only the next day that I returned to this post realising that "this question" isn't even defined.

33% innit

100 **** percent, i'm all in!

I argue it's still 25%, because the answer is either a,b,c, or d, you can only choose 1, regardless of the possible answer having two slots.

Since two of them are the same, you have a 50% chance of picking something that is 33% of the possible answers. The other two, you have 25% chance of picking something that us 33% of the possible answers.

So 50%33% + 2 (33%*25%)= 33%

So your chances of being right is 33% cause there is effectively 3 choices.

Ahhhhhhhhhhhhhhhhh

Any answer is correct as long as you don't pick it at random. I'd choose (a) because I'm too lazy to read the other options

I would think a b c d so 25% O he made a mistake znd forgot to take the bubble answer out. Now we only can pick between aord b c so it would be 33%

Seems my logic is wrong iff i read the rest

The answer is clear

60%

I choose 75%

There is absolutely no way it is 60%. Because you can never have 60% chances of picking anything particular when there are only 4 choices. Knowing this, the answer is either 25% or 50%. Two effective choices, so the answer is C, 50%.

B) 60% because I'm generally very lucky.

Yes

Selecting not at random, A xor D must be correct, because the answer key can only have one correct answer so even duplicate right answers must also be wrong.

Great! I'll hand this to my daughter to annoy her co-students who struggle with probabilitiy ;-)

Can I take a 50/50 joker first?

I asked Google to roll a D4 and it rolled a 4. So my answer (correct or not) when following the directions in the question is the fourth one (D).

It's annoying that 25% appears twice. How about these answers:

a) 100%

b) 75%

c) 50%

d) 0%